10x^2+14x-227=0

Solution for 10x^2+14x-227=0 equation:

10x^2+14x-227=0

a = 10; b = 14; c = -227;
Δ = b2-4ac
Δ = 142-4·10·(-227)
Δ = 9276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9276}=\sqrt{4*2319}=\sqrt{4}*\sqrt{2319}=2\sqrt{2319}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{2319}}{2*10}=\frac{-14-2\sqrt{2319}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{2319}}{2*10}=\frac{-14+2\sqrt{2319}}{20}
$